to: Why the converter is unable to feed the peak current directly
in Category: FAQ
Category
- Products
-
- Wiki
- Contact us
Inverter manufacturers
sales@inverters.cn
<- - Back to Why the converter is unable to feed the peak current directly - ->
One reason why the converter is unable to feed the peak current directly is because of its own source (output) impedance limitations. One could consider feed-forward technique to address this problem.Let me assume that this is Lsource, say it is predominantly inductive. In that case, the feed-forward voltage required to overcome this effect is dff, where
vff = Lsource*delta(Ipk)/deltat
Where delta(Ipk)/deltat is the rate of change of peak current.
dff = vff/Vdcmax
where
dff is the dutycycle required to produce vff
Thus,
Dtot = Derr+dff
Where
Dtot = total dutycycle fed to the switch
Derr = dutycycle from the error controller
Obviously, this requires the load current to be fed back for the calculation. I am assuming this should not be an issue since the output current will be close loop controlled.
Knowing the converter output impedance will also help you determine the physical limitations of the converter in meeting the peak current requirements as well.